Monday, July 07, 2014

2014 Neco June/July Mathematics Essay Questions and Answers Is Available Here.

Type A
1. DBBADBABEE
11.CABBEEBBBC
21.BCDEBCBCDB
31.AEBCDAEDBD
41.ABADCEBAED
51.BEBDBEDEDA


Type .B
1- 10: CDDDDBBDBD
11 – 20: CBECCCBCBB
21 – 30: CCBEBDADEE
31 – 40 BAEAEDDDCC
41 – 50 DEDB – - – - – -
51 – 60 – - – - – - CCEB.
Maths TYPE C
1-10: BEBDAEDEDA
11-20: EDAEBBDBAB
21-30: ADADDCABEA
31-40: AABBCAEDDB
41-50: DBDBABBBCC
51-60: BBBAEBABEE.
Maths Type D
1-10: ABADCEBAED
11-20: BBBAEBABEE
21-30: AEBCDAEDDB
31-40: DCDEBCBCDB
41-50: BEBDBEDEDA
51-60: CABBEEBABC
++++++++++++++++++++++++++++++++++++++
2) Y= a + b 1/?x
When y=2, x=1 and y=6, x=4
The relationship = Y= a+b 1/?x
2 = a + b 1/?1————(I)
6 = a + b 1/?4————(ii)
2 = a + b————- (I)
6 = a + 0.5b———(ii)
-a + b =2
a – 0.5b=6
———————
0.5b = -4
b= 2
Put b in equ 1
2 = a+b
2 = a+2
a = 0
2aii) Determine the value of y, when x=9
Y= a + b 1/?x
Y = 0 + 2 1/?9
Y= 0 + 2(1/3)
Y= 0+2/3 , = 2/3
3a) Given that V= ?gx (1+3h)
V^2 = gx ( 1 + 3h )
V^2 = gx + gx ( 3h/x)
V^2 – gx = gx3h/x
X( V^2 – gx ) = gx3h
X^2 V^2 – gx^2 = gx3h
h = x^2 V^2 – gx^2/3gx. (Where ^ is
raise to power)
3b) Value of H, when V=25 , g=10, x=15
h(15^2 x 25^2) – ( 10 x 15^2 )/ 3 x 10 x
15
h( 225. X 625) – (2250)/ 450
h( 138,375)/450
h= 307.5
4a) The sum of in interior angles of a
n- side convex polygone is ( 2n-4 )
right angles
3:2 ( interior and exterior )
( n-2 )180 = 360o
X(3-2 x 180)= 360o
360/180
X= 2
4b). Xy=14cm, XZ=7cm, PZ=3cm, YP=?
PZ/YB = XZ/XY
52/7 = 7YB/7
YB= 7.43cm
YZ = PZ + YB
YZ = 3 + 7.43
YZ= 10.43cm
5a) a+b+c+d+e+f+g+h/8 = 10 ——— (I)
a+b+c+d+e+f+g/7 = 9 ———– (ii)
a+b+c+d+e+f+g+h = 80
a+b+c+d+e+f+g+ = 63
h= 80-63
h= 17
5b) Rice —— 2
Pineapple —–3
Cassava …….6
Sugarcane—- 4
Cocoa————5
TOTAL::::::: 20
* Rice = 2/20 x 360 = 36
* Pinaple = 3/20 x 360 = 54
* casava = 6/20 x 360 = 108
* sugar = 4/20 x 360 = 80
* cocoa = 5/20 x 360 = 90
7ai) Materia = 3
Labour = 5
Profit————–» 23%
Materials = 3/8 x 95000
= #35,625
Profit of materials at 23%
= 23/100 x 35625
= #819.751
At 23% profit the material cost
#35625 + #8193.7
= # 43818.75
At 18% = 18/100 x 35625
= #6412.5
Cost sold to consumer
=# 35.625 + 6412.5
= # 42,037.5
7aii) Labour = 5/8 x 95000
= 59,375
7b) cost of materials = #35,625
Since there is no increase in the cost
of labour
15/100 x 35,625
= # 5343.75
The 15% increase = 35,625 + 5343.7
#40,968.75
12a)
X. | No of absent | Fx.
1. | 40. | 40
2. | x. | 2x
3. | 25. | 75
4. | 50. | 200
5. | 35. | 175
6. | 2x. | 12x
Total. | Ef=150+3x. | Efx= 490+14x
To find the value of x, since the total
number of absents
Ef = 240
150+3x = 240
3x = 240-150
3x= 90
X= 90/3, 30
If x= 30 , Ef = 150+3(30)=24
Efx = 490 + 14(30) = 910
Mean = Efx/Ef
= 910/240
= 3.79
* Absent for six days
= 2 x 30
= 60 absent
* at least a day
40 + x + 25 + 50
40 + 30 + 25 + 50 = 145 absent.

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